For a real gas, the chemical potential is given by
A. RT dlnP
B. RT dlnf
C. R dlnf
D. None of these
Answer: Option B
Solution (By Examveda Team)
We know the property relation $$dG=VdP-sdT$$ for constant temperature $$dT=0$$For an ideal gas
$$\eqalign{ & dG = VdP \cr & dG = \frac{{RT}}{P}dP \cr & \Rightarrow dG = RTdlnP \cr} $$
For a real gas also if we want to describe the relation in the same functional form we express it as $$dG = RTd \,ln\, f \Rightarrow d\mu = RTd \,ln\, f$$ where $$f=$$ fugacity, that means we buried the entire non ideality in this term fugacity. The term fugacity is also called as effective pressure.

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