For a reversible process involving only pressure-volume work
A. (dF)T, P < 0
B. (dF)T, P > 0
C. (dF)T, P = 0
D. (dA)T, V < 0
Answer: Option C
Solution(By Examveda Team)
Here the $$F$$ is Gibbs free energy and $$A$$ is Helmholtz free energy.Since for an reversible process $$Tds = dU + PdV$$
For, constant temperature and constant pressure process the above equation can be written as
$$\eqalign{ & d\left( {TS - U} \right) = PdV \cr & \Rightarrow d\left( { - A} \right) > PdV \cr & \Rightarrow {\left( {dF} \right)_{T,\,P}} = 0. \cr} $$
For reversible process.
Related Questions on Chemical Engineering Thermodynamics
A. Maxwell's equation
B. Thermodynamic equation of state
C. Equation of state
D. Redlich-Kwong equation of state
Henry's law is closely obeyed by a gas, when its __________ is extremely high.
A. Pressure
B. Solubility
C. Temperature
D. None of these
A. Enthalpy
B. Volume
C. Both A & B
D. Neither A nor B
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