For a spin s particle, in the eigen basis of $$\overrightarrow {{{\bf{s}}^2}} ,$$ sz the expectation value $$\left\langle {sm\left| {\overrightarrow {{\bf{s}}_x^2} } \right|sm} \right\rangle $$ is
A. $$\frac{{\hbar \left\{ {s\left( {s + 1} \right) - {m^2}} \right\}}}{2}$$
B. $$\hbar \left\{ {s\left( {s + 1} \right) - 2{m^2}} \right\}$$
C. $${\hbar \left\{ {s\left( {s + 1} \right) - {m^2}} \right\}}$$
D. $${\hbar ^2}{m^2}$$
Answer: Option A
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