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For an equilateral triangle, the ratio of the in-radius and the outer-radius is
Answer & Solution
Correct Answer:
Option
A
Let the side of equilateral ΔABC be a & r = in-radius & R = outer radius
$$\eqalign{ & r = \frac{a}{{2\sqrt 3 }},\,\,\,R = \frac{a}{{\sqrt 3 }} \cr & r:R = \frac{a}{{2\sqrt 3 }}:\frac{a}{{\sqrt 3 }} = 1:2 \cr} $$
$$\eqalign{ & r = \frac{a}{{2\sqrt 3 }},\,\,\,R = \frac{a}{{\sqrt 3 }} \cr & r:R = \frac{a}{{2\sqrt 3 }}:\frac{a}{{\sqrt 3 }} = 1:2 \cr} $$
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