For an ideal gas,
A. $${\left( {\frac{{\partial p}}{{\partial T}}} \right)_V}{\left( {\frac{{\partial T}}{{\partial V}}} \right)_p}{\left( {\frac{{\partial V}}{{\partial p}}} \right)_T} = 0$$
B. $${\left( {\frac{{\partial p}}{{\partial T}}} \right)_V}{\left( {\frac{{\partial T}}{{\partial V}}} \right)_p}{\left( {\frac{{\partial V}}{{\partial p}}} \right)_T} = - 1$$
C. $${\left( {\frac{{\partial p}}{{\partial T}}} \right)_V}{\left( {\frac{{\partial T}}{{\partial V}}} \right)_p}{\left( {\frac{{\partial V}}{{\partial p}}} \right)_T} = + 1$$
D. $${\left( {\frac{{\partial p}}{{\partial T}}} \right)_V}{\left( {\frac{{\partial T}}{{\partial V}}} \right)_p}{\left( {\frac{{\partial V}}{{\partial p}}} \right)_T} = + 2$$
Answer: Option A
This Question Belongs to Engineering Chemistry >> Chemical And Ionic Equilibrium
A. 6.0 × 10-4, 3.0 × 10-4, 1.5 × 10-3
B. 6.0 × 10-4, 3.0 × 10-4, 9 × 10-4
C. 5.0 × 10-4, 3.5 × 10-4, 13.5 × 10-3
D. 5.0 × 10-4, 3.5 × 10-4, 8.5 × 10-4
Among the following, the equilibrium which is not affected by an increase in pressure is
A. 2SO3(g) $$ \rightleftharpoons $$ 2SO2(g) + O2(g)
B. H2(g) + l2(s) $$ \rightleftharpoons $$ 2HI(g)
C. C(s) + H2O(g) $$ \rightleftharpoons $$ CO(g) + H2(g)
D. 3Fe(s) + 4H2O(g) $$ \rightleftharpoons $$ Fe3O4(s) + 4H2(g)
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