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For an ideal gas, the chemical potential is given by
Answer & Solution
Correct Answer:
Option
A
Since for an ideal gas mixture : $$fugacity= pressure$$
\[\begin{array}{l} d\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\smile$}} \over G} = RTdlnP\\ \Rightarrow d{\mu _i} = RTdlnP \end{array}\]
\[\begin{array}{l} d\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\smile$}} \over G} = RTdlnP\\ \Rightarrow d{\mu _i} = RTdlnP \end{array}\]
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