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For equilibrium process (i e reversible) in an isolated system

This question belongs to Chemical Engineering Chemical Engineering Thermodynamics
Chemical Engineering Thermodynamics
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For equilibrium process (i.e. reversible) in an isolated system

Answer & Solution
Correct Answer: Option A
Since in case of reversible or equilibrium process $$\delta Q = TdS$$   and for isolated system $$\delta Q = 0$$
So, $$dS=0$$
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