For equilibrium process (i.e. reversible) in an isolated system
A. ds = 0
B. ds < 0
C. ds > 0
D. ds = Constant
Answer: Option A
Solution (By Examveda Team)
Since in case of reversible or equilibrium process $$\delta Q = TdS$$ and for isolated system $$\delta Q = 0$$So, $$dS=0$$
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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