For spontaneous changes in an isolated system (S = entropy)
A. Ds = 0
B. Ds <0
C. Ds > 0
D. Ds = Constant
Answer: Option C
Solution (By Examveda Team)
By second law of thermodynamics the \[TdS \ge \delta Q\]For an isolated system \[\delta Q = 0\]
\[ \Rightarrow \] for an irreversible (nothing but spontaneous process) \[dS > 0\] and for an reversible (or the system at equilibrium) \[dS = 0\]
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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