For the equation, $$\frac{{{\text{dy}}}}{{{\text{dx}}}} + 7{{\text{x}}^2}{\text{y}} = 0,$$ if $${\text{y}}\left( {\text{0}} \right) = \frac{3}{7},$$ then the value of y(1) is
A. $$\frac{3}{7}{{\text{e}}^{ - \frac{7}{3}}}$$
B. $$\frac{7}{3}{{\text{e}}^{ - \frac{7}{3}}}$$
C. $$\frac{3}{7}{{\text{e}}^{ - \frac{3}{7}}}$$
D. $$\frac{7}{3}{{\text{e}}^{ - \frac{3}{7}}}$$
Answer: Option A
A. $${\text{y}} = \left( {{{\text{C}}_1} - {{\text{C}}_2}{\text{x}}} \right){{\text{e}}^{\text{x}}} + {{\text{C}}_3}\cos {\text{x}} + {{\text{C}}_4}\sin {\text{x}}$$
B. $${\text{y}} = \left( {{{\text{C}}_1} + {{\text{C}}_2}{\text{x}}} \right){{\text{e}}^{\text{x}}} - {{\text{C}}_2}\cos {\text{x}} + {{\text{C}}_4}\sin {\text{x}}$$
C. $${\text{y}} = \left( {{{\text{C}}_1} + {{\text{C}}_2}{\text{x}}} \right){{\text{e}}^{\text{x}}} + {{\text{C}}_3}\cos {\text{x}} + {{\text{C}}_4}\sin {\text{x}}$$
D. $${\text{y}} = \left( {{{\text{C}}_1} + {{\text{C}}_2}{\text{x}}} \right){{\text{e}}^{\text{x}}} + {{\text{C}}_3}\cos {\text{x}} - {{\text{C}}_4}\sin {\text{x}}$$
A. $$\sqrt {1 - {{\text{x}}^2}} = {\text{c}}$$
B. $$\sqrt {1 - {{\text{y}}^2}} = {\text{c}}$$
C. $$\sqrt {1 - {{\text{x}}^2}} + \sqrt {1 - {{\text{y}}^2}} = {\text{c}}$$
D. $$\sqrt {1 + {{\text{x}}^2}} + \sqrt {1 + {{\text{y}}^2}} = {\text{c}}$$

Join The Discussion