For the reaction, N2(g) + 3H2(g) → 2NH3(g)
compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.
| Data | Species S°(J/K/mol) |
NH3(g) 192.3 |
N2(g) 191.5 |
H2(g) 130.6 |
A. ΔS° = -37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction
B. ΔS° = -198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction
C. ΔS° = -31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction
D. ΔS° = +31.25 J/K/mol; positive sign indicates that the reaction is spontaneous
Answer: Option B
This Question Belongs to Engineering Chemistry >> Chemical Thermodynamics
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