For water at 300°C, it has a vapour pressure 8592.7 kPa and fugacity 6738.9 kPa Under these conditions, one mole of water in liquid phase has a volume of 25.28 cm³ and that in vapour phase in 391.1 cm³. Fugacity of water (in kPa) at 9000 kPa will be

A. 6738.9

B. 6753.5

C. 7058.3

D. 9000

Answer: Option B

Solution(By Examveda Team)

We know $$\ln \left( {\frac{f}{{{f^{sat}}}}} \right) = \frac{v}{{RT}}\left( {p - {p^{sat}}} \right)$$      substituting the suitable values we will get $$f=6753.5$$