Fourier's law of heat conduction is (where Q = Amount of heat flow through the body in unit time, A = Surface area of heat flow, taken at right angles to the direction of heat flow, dT = Temperature difference on the two faces of the body, dx = Thickness of the body, through which the heat flows, taken along the direction of heat flow and k = Thermal conductivity of the body)
A. $${\text{kA}}\frac{{{\text{dT}}}}{{{\text{dx}}}}$$
B. $${\text{kA}}\frac{{{\text{dx}}}}{{{\text{dT}}}}$$
C. $${\text{k}}\frac{{{\text{dT}}}}{{{\text{dx}}}}$$
D. $${\text{k}}\frac{{{\text{dx}}}}{{{\text{dT}}}}$$
Answer: Option A
Solution (By Examveda Team)
Fourier's law of heat conduction is $${\text{kA}}\frac{{{\text{dT}}}}{{{\text{dx}}}}$$Where Q = Amount of heat flow through the body in unit time, A = Surface area of heat flow, taken at right angles to the direction of heat flow, dT = Temperature difference on the two faces of the body, dx = Thickness of the body, through which the heat flows, taken along the direction of heat flow and k = Thermal conductivity of the body.
The law of heat conduction, also known as Fourier's law, states that the time rate of heat transfer through a material is proportional to the negative gradient in the temperature and to the area, at right angles to that gradient, through which the heat flows.
This Question Belongs to Mechanical Engineering >> Heat And Mass Transfer
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