Fundamental momentum equation for a hydraulic jump, is
A. $${\text{D}}_1^2 - {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} - {{\text{V}}_2}} \right)$$
B. $${\text{D}}_2^2 - {\text{D}}_1^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} - {{\text{V}}_2}} \right)$$
C. $${\text{D}}_1^2 - {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} - {{\text{V}}_1}} \right)$$
D. $${\text{D}}_1^2 + {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} - {{\text{V}}_1}} \right)$$
Answer: Option B
This Question Belongs to Civil Engineering >> Irrigation Engineering
Option B should be D₂² - D₁² = (2q/g) × (V1 - V2)