Fundamental momentum equation for a hydraulic jump, is
A. $${\text{D}}_1^2 - {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} - {{\text{V}}_2}} \right)$$
B. $${\text{D}}_2^2 - {\text{D}}_1^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} - {{\text{V}}_2}} \right)$$
C. $${\text{D}}_1^2 - {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} - {{\text{V}}_1}} \right)$$
D. $${\text{D}}_1^2 + {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} - {{\text{V}}_1}} \right)$$
Answer: Option B
This Question Belongs to Civil Engineering >> Irrigation Engineering
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A. Protection of banks erosion by the waves
B. Control of seepage losses
C. Strengthening of banks
D. All the above
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A. Drains
B. Inundation canals
C. Valley canals
D. Contour canals
A hydroelectric scheme operating under a head of 80 m will be classified as
A. low head scheme
B. medium head scheme
C. high head scheme
D. none of the above
A. Low sodium water
B. Medium sodium water
C. High sodium water
D. Very high sodium water
Option B should be D₂² - D₁² = (2q/g) × (V1 - V2)