Gibbs free energy per mole for a pure substance is equal to the
A. Latent heat of vaporisation
B. Chemical potential
C. Molal boiling point
D. Heat capacity
Answer: Option B
Solution(By Examveda Team)
The chemical potential is nothing but partial molar gibbs free energy (since the partial molar functions tells about the change in total molar property with change in composition(moles) we consider partial molar functions as intensive properties),$${\mu _i} = \left( {\frac{{\partial nG}}{{\partial {n_i}}}} \right)T,P,{n_j}$$
When there is only one component ,G(total molar gibbs free energy) becomes independent of composition(intensive property ) so the equation becomes $${\mu _i} = G\left( {\frac{{\partial {n_I}}}{{\partial {n_i}}}} \right)T,P,{n_j}$$
Hence, $${\mu _i} = G$$
Related Questions on Chemical Engineering Thermodynamics
A. Maxwell's equation
B. Thermodynamic equation of state
C. Equation of state
D. Redlich-Kwong equation of state
Henry's law is closely obeyed by a gas, when its __________ is extremely high.
A. Pressure
B. Solubility
C. Temperature
D. None of these
A. Enthalpy
B. Volume
C. Both A & B
D. Neither A nor B
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