Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to?
A. 1.45
B. 1.88
C. 2.9
D. 3.7
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {10^{0.48}} = x{\text{ }} \cr & {10^{0.70}} = y{\text{ }} \cr & {\text{and }}{x^z} = {y^2} \cr & \therefore {\left( {{{10}^{0.48}}} \right)^z} = {\left( {{{10}^{0.70}}} \right)^2} \cr & \Rightarrow {10^{0.48z}} = {10^{1.40}} \cr} $$If ax = ay, if base equal power are equal : (x = y)
$$\eqalign{ & \therefore 0.48z = 1.40 \cr & \Rightarrow z = \frac{{140}}{{48}} \cr & \Rightarrow z = \frac{{35}}{{12}} \cr & \Rightarrow z = 2.9 \cr} $$
Join The Discussion
Comments ( 1 )
Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
It will be...
x^z= y2