Given the program of naive method.
for i=1 to n do
for j=1 to n do
Z[i][j]=0;
for k=1 to n do
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Fill in the blanks with appropriate formula
for i=1 to n do
for j=1 to n do
Z[i][j]=0;
for k=1 to n do
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A. Z[i][j] = Z[i][j] + X[i][k]*Y[k][j]
B. Z[i][j] = Z[i][j] + X[i][k] + Y[k][j]
C. Z[i][j] = Z[i][j] * X[i][k]*Y[k][j]
D. Z[i][j] = Z[i][j] * X[i][k] + Y[k][j]
Answer: Option A
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