How do you specify that a function may throw an exception in C++?

Solution (By Examveda Team)

The correct answer is Option D: Using the 'noexcept' specifier
Here's why:
Exception handling in C++ allows you to deal with unexpected problems that occur during the execution of a program.
A function can signal that something went wrong by "throwing" an exception.

Let's break down the options:
Option A: Using the 'throws' keyword - The `throws` keyword is not used in standard C++ for specifying exceptions. Languages like Java use `throws`.
Option B: Using the 'exception' keyword - The `exception` keyword is related to exception classes but not to specifying if a function *might* throw an exception.
Option C: Using the 'throws()' specifier - This is also incorrect. C++11 introduced `noexcept` for this purpose. Older C++ standards used something called exception specifications but they are largely deprecated and not the best practice to use anymore.
Option D: Using the 'noexcept' specifier - The `noexcept` specifier is used to specify whether a function may throw an exception. If a function is declared `noexcept`, it promises *not* to throw any exceptions. If it *does* throw an exception, the program might terminate abruptly. The absence of `noexcept` does *not* mean the function *will* throw, only that it *might*.