How many ways can 4 prizes be given away to 3 boys, if each boy is eligible for all the prizes?
A. 256
B. 24
C. 12
D. None of these
Answer: Option B
Solution (By Examveda Team)
Let the 3 boys be B1, B2, B3 and 4 prizes be P1, P2, P3 and P4 Now B1 is eligible to receive any of the 4 available prizes (so 4 ways) B2 will receive prize from rest 3 available prizes(so 3 ways) B3 will receive his prize from the rest 2 prizes available(so 2 ways) So total ways would be: 4 × 3 × 2 × 1 = 24 Ways Hence, the 4 prizes can be distributed in 24 waysThis Question Belongs to Arithmetic Ability >> Permutation And Combination
How many ways can 4 prizes be given away to 3 boys, if each boy is eligible for all the prizes?
correct answer 81
nowhere in ques is mentioned that repetition is not allowed... and so it can be 3^4
sir iss question m bola gya h.. that if each boy is eligible for ALL the prize... then the total ways must be 4*4*4 because 1st boy can get all the prize similarly 2nd boy nd 3rd boy too