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How many ways can 4 prizes be given away to 3 boys, if each boy is eligible for all the prizes?

A. 256

B. 24

C. 12

D. None of these

Answer: Option B

Solution(By Examveda Team)

Let the 3 boys be B1, B2, B3 and 4 prizes be P1, P2, P3 and P4
Now B1 is eligible to receive any of the 4 available prizes (so 4 ways)
B2 will receive prize from rest 3 available prizes(so 3 ways)
B3 will receive his prize from the rest 2 prizes available(so 2 ways)
So total ways would be: 4 × 3 × 2 × 1 = 24 Ways
Hence, the 4 prizes can be distributed in 24 ways

This Question Belongs to Arithmetic Ability >> Permutation And Combination

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Comments ( 3 )

  1. Deepak Goyal
    Deepak Goyal :
    4 years ago

    How many ways can 4 prizes be given away to 3 boys, if each boy is eligible for all the prizes?
    correct answer 81

  2. Tejaswi Sagi
    Tejaswi Sagi :
    6 years ago

    nowhere in ques is mentioned that repetition is not allowed... and so it can be 3^4

  3. Uravashi Sharma
    Uravashi Sharma :
    6 years ago

    sir iss question m bola gya h.. that if each boy is eligible for ALL the prize... then the total ways must be 4*4*4 because 1st boy can get all the prize similarly 2nd boy nd 3rd boy too

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