How many ways can 4 prizes be given away to 3 boys, if each boy is eligible for all the prizes?
A. 256
B. 24
C. 12
D. None of these
Answer: Option B
Solution(By Examveda Team)
Let the 3 boys be B1, B2, B3 and 4 prizes be P1, P2, P3 and P4 Now B1 is eligible to receive any of the 4 available prizes (so 4 ways) B2 will receive prize from rest 3 available prizes(so 3 ways) B3 will receive his prize from the rest 2 prizes available(so 2 ways) So total ways would be: 4 × 3 × 2 × 1 = 24 Ways Hence, the 4 prizes can be distributed in 24 waysJoin The Discussion
Comments ( 3 )
Related Questions on Permutation and Combination
A. 3! 4! 8! 4!
B. 3! 8!
C. 4! 4!
D. 8! 4! 4!
A. 7560,60,1680
B. 7890,120,650
C. 7650,200,4444
D. None of these
A. 8 × 9!
B. 8 × 8!
C. 7 × 9!
D. 9 × 8!
How many ways can 4 prizes be given away to 3 boys, if each boy is eligible for all the prizes?
correct answer 81
nowhere in ques is mentioned that repetition is not allowed... and so it can be 3^4
sir iss question m bola gya h.. that if each boy is eligible for ALL the prize... then the total ways must be 4*4*4 because 1st boy can get all the prize similarly 2nd boy nd 3rd boy too