D is the diameter of a circular sewer and $$\alpha $$ is the side of a square section sewer. If both are hydraulically equivalent, the relationship which holds good, is

A. $$\pi {{\text{D}}^{\frac{8}{3}}} = 4{{\text{b}}^{\frac{8}{3}}}$$

B. $$\pi {{\text{D}}^{\frac{3}{8}}} = 4{{\text{b}}^{\frac{3}{8}}}$$

C. $$\pi {{\text{D}}^{\frac{2}{3}}} = 4{{\text{b}}^{\frac{2}{3}}}$$

D. $$\pi {{\text{D}}^{\frac{3}{2}}} = 4{{\text{b}}^{\frac{3}{3}}}$$

Answer: Option A