?
If 1 < x < 2, then the value of $$\sqrt {{{\left( {x - 1} \right)}^2}} {\text{ + }}\sqrt {{{\left( {3 - x} \right)}^2}} {\text{ is?}}$$
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& 1 < x < 2 \cr
& \sqrt {{{\left( {x - 1} \right)}^2}} {\text{ + }}\sqrt {{{\left( {3 - x} \right)}^2}} \cr
& \left( {{\text{Square root cancel with square}}} \right) \cr
& \therefore x - 1 + 3 - x \cr
& = 2 \cr} $$
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