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If $$\frac{1}{{{x^2} + {a^2}}} = {x^2} - {a^2},$$ then the value of x is:
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& \frac{1}{{{x^2} + {a^2}}} = {x^2} - {a^2} \cr
& 1 = {x^4} - {a^4} \cr
& {x^4} = 1 + {a^4} \cr
& x = {\left( {1 + {a^4}} \right)^{\frac{1}{4}}} \cr} $$
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