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If 2% solution of a sewage sample is incubated for 5 days at 20°C and depletion of oxygen was found to be 5 ppm, B.O.D. of the sewage is

A. 200 ppm

B. 225 ppm

C. 250 ppm

D. None of these

Answer: Option C


This Question Belongs to Civil Engineering >> Waste Water Engineering

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Comments ( 2 )

  1. Subhransu Sekhar
    Subhransu Sekhar :
    3 years ago

    BOD of sewage=dilution factor*Dissolved oxygen
    D.f=100/2
    D.o=5
    BOD of sewage=100/2*5=250ppm

  2. Shiv Shakti
    Shiv Shakti :
    4 years ago

    Can any one post the solution?

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