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If 2% solution of a sewage sample is incubated for 5 days at 20°C and depletion of oxygen was found to be 5 ppm, B.O.D. of the sewage is

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Correct Answer: Option C
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2 Comments
Subhransu Sekhar
Subhransu Sekhar 5 years ago
BOD of sewage=dilution factor*Dissolved oxygen
D.f=100/2
D.o=5
BOD of sewage=100/2*5=250ppm
Shiv Shakti
Shiv Shakti 6 years ago
Can any one post the solution?