If 2% solution of a sewage sample is incubated for 5 days at 20°C and depletion of oxygen was found to be 5 ppm, B.O.D. of the sewage is
A. 200 ppm
B. 225 ppm
C. 250 ppm
D. None of these
Answer: Option C
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BOD of sewage=dilution factor*Dissolved oxygen
D.f=100/2
D.o=5
BOD of sewage=100/2*5=250ppm
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