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If $$\left( {2 + \sqrt 3 } \right)a$$ = $$\left( {2 - \sqrt 3 } \right)b$$ = 1 then the value of $$\frac{1}{a}$$ + $$\frac{1}{b}$$ is?
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& \left( {2 + \sqrt 3 } \right)a = \left( {2 - \sqrt 3 } \right)b = 1 \cr
& \Rightarrow \frac{1}{a} = \left( {2 + \sqrt 3 } \right) \cr
& {\text{By rationals}} \cr
& \Rightarrow \frac{1}{b} = \left( {2 - \sqrt 3 } \right) \cr
& \Rightarrow \frac{1}{a} + \frac{1}{b} = 2 + \sqrt 3 + 2 - \sqrt 3 \cr
& \Rightarrow \frac{1}{a} + \frac{1}{b} = 4 \cr} $$
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