?
If 2x2 + 5x + 1 = 0, then one of the value of $$x - \frac{1}{{2x}}$$ is:
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& 2{x^2} + 5x + 1 = 0 \cr
& 2{x^2} + 1 = - 5x \cr
& 2x + \frac{1}{x} = - 5 \cr
& {\text{divide '2' both sides}} \cr
& x + \frac{1}{{2x}} = - \frac{5}{2} \cr
& a - b = \sqrt {{{\left( {a + b} \right)}^2} - 4ab} \cr
& x - \frac{1}{{2x}} = \sqrt {{{\left( { - \frac{5}{2}} \right)}^2} - 4 \times x \times \frac{1}{{2x}}} \cr
& = \sqrt {\frac{{25}}{2} - 2} \cr
& = \frac{{\sqrt {17} }}{2} \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login