If 2x2 + y2 + 6x - 2xy + 9 =...

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If 2x² + y² + 6x - 2xy + 9 = 0, then the value of (4x³ - y³ + x²y²) is:

A. 0

B. 9

C. -3

D. -9

Answer: Option A

Solution (By Examveda Team)

2x² + y² + 6x - 2xy + 9 = 0
x² + x² + y² + 6x - 2xy + 9= 0
(x² + y² - 2xy) + (x² + 6x + 9) = 0
(x - y)² + (x + 3)² = 0
x = y, x = -3
4x³ - y³ + x²y²
= 4x³ - x³ + x⁴
= 3x³ + x⁴
= -x⁴ + x⁴
= 0

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If 2x2 + y2 + 6x - 2xy + 9 =...

If 2x2 + y2 + 6x - 2xy + 9 = 0, then the value of (4x3 - y3 + x2y2) is:

Solution (By Examveda Team)

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If 2x² + y² + 6x - 2xy + 9 = 0, then the value of (4x³ - y³ + x²y²) is: