If 3x2 - 5x + 1 = 0, then the value of $$\left( {{x^2} + \frac{1}{{9{x^2}}}} \right)$$ is:
A. $$1\frac{2}{3}$$
B. $$1\frac{1}{3}$$
C. $$2\frac{1}{9}$$
D. $$2\frac{1}{3}$$
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & 3x\left( {x - \frac{5}{3} + \frac{1}{{3x}}} \right) = 0 \cr & x + \frac{1}{{3x}} = \frac{5}{3} \cr & {x^2} + \frac{1}{{9{x^2}}} + \frac{2}{3} = \frac{{25}}{9} \cr & {x^2} + \frac{1}{{9{x^2}}} = \frac{{25 - 6}}{9} \cr & {x^2} + \frac{1}{{9{x^2}}} = \frac{{19}}{9} \cr & {x^2} + \frac{1}{{9{x^2}}} = 2\frac{1}{9} \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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