If $${4^{4x + 1}} = \frac{1}{{64}}{\text{,}}$$   then the value of x is?

A. $$\frac{1}{2}$$

B. -1

C. $$ - \frac{1}{2}$$

D. $$ - \frac{1}{6}$$

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {4^{4x + 1}} = \frac{1}{{64}} \cr & \Rightarrow {4^{4x + 1}} = \frac{1}{{{{\left( 4 \right)}^3}}} \cr & \Rightarrow {4^{4x + 1}} = {\left( 4 \right)^{ - 3}} \cr & \Rightarrow 4x + 1 = - 3 \cr & \Rightarrow 4x = - 4 \cr & \Rightarrow x = - 1 \cr} $$