If 47.2506 = 4A + 7B + 2C + $$\frac{5}{{\text{D}}}$$ + 6E, then the value of 5A + 3B + 6C + D + 3E is?

A. 53.6003

B. 53.603

C. 153.6003

D. 213.0003

Answer: Option C

Solution(By Examveda Team)

Given 47.2506 = 4A + 7B + 2C + $$\frac{5}{{\text{D}}}$$ + 6E . . . . . . . . (1)
Now, we can write 47.2506 = 40 + 7 + 0.2 + 0.05 + 0.0006 . . . . . . . . (2)
Comparing (1) and (2) we get
4A = 40 ⇒ A = 10
$7B = 7 ⇒ B = 1
2C = 0.2 ⇒ C = 0.1
$$\frac{5}{{\text{D}}}$$ = 0.05 ⇒ D = $$\frac{5}{{0.05}}$$ = 100
and, 6E = 0.0006 ⇒ E = 0.0001
So velue of 5A + 3B + 6C + D + 3E
= (5 × 10) + (3 × 1) + (6 × 0.1) + 100 + (3 × 0.0001)
= 50 + 3 + 0.6 + 100 + 0.0003
= 153.6003