If (5√5x3 - 3√3y3) ÷ (√5x - √3y) = (Ax2 + By2 + Cxy), then what is the value of (3A - B - $$\sqrt {15} $$ C)?
A. 12
B. 8
C. -3
D. -5
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \left( {5\sqrt 5 {x^3} - 3\sqrt 3 {y^3}} \right) \div \left( {\sqrt 5 x - \sqrt 3 y} \right) = A{x^2} + B{y^2} + Cxy \cr & 3A - B - \sqrt {15} C = ? \cr & \frac{{{{\left( {\sqrt 5 x} \right)}^3} - {{\left( {\sqrt 3 x} \right)}^3}}}{{\sqrt 5 x - \sqrt 3 y}} = A{x^2} + B{y^2} + Cxy \cr & 5{x^2} + 3{y^2} + \sqrt {15} xy \cr & A = 5,\,B = 3,\,C = \sqrt {15} \cr & 3A - B - \sqrt {15} C \cr & = 3 \times 5 - 3 - \sqrt {15} \times \sqrt {15} \cr & = - 3 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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