If $${64^{x + 1}} = \frac{{64}}{{{4^x}}}{\text{,}}$$ then the value of x is?
A. 1
B. 0
C. $$\frac{1}{2}$$
D. 2
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {64^{x + 1}} = \frac{{64}}{{{4^x}}} \cr & \Rightarrow {\left( {{4^3}} \right)^{x + 1}} - \frac{{{4^3}}}{{{4^x}}} \cr & \Rightarrow {4^{3x + 3}} = {4^{3 - x}} \cr & \Rightarrow 3x + 3 = 3 - x \cr & \Rightarrow 4x = 0 \cr & \Rightarrow x = 0 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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