If [8(x + y)3 - 27(x - y)3] ÷ (5y - x) = Ax2 + Bxy + Cy2, then the value of (A + B + C) is:
A. 26
B. 19
C. 16
D. 13
Answer: Option C
Solution(By Examveda Team)
[8(x + y)3 - 27(x - y)3] ÷ (5y - x) = Ax2 + Bxy + Cy2Let, x = 1, y = 1
[8(1 + 1)3 - 27 × 0] ÷ (5 - 1) = (A + B + C)
$$\frac{{8 \times 8}}{4}$$ = A + B + C
16 = A + B + C
This Question Belongs to Arithmetic Ability >> Algebra
Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
Join The Discussion