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If 8(x + y)3 - 27(x - y)3 (5y - x)...

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Algebra
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If [8(x + y)3 - 27(x - y)3] ÷ (5y - x) = Ax2 + Bxy + Cy2, then the value of (A + B + C) is:

Answer & Solution
Correct Answer: Option C
[8(x + y)3 - 27(x - y)3] ÷ (5y - x) = Ax2 + Bxy + Cy2
Let, x = 1, y = 1
[8(1 + 1)3 - 27 × 0] ÷ (5 - 1) = (A + B + C)
$$\frac{{8 \times 8}}{4}$$  = A + B + C
16 = A + B + C
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