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If 9x2 + y2 = 37 and xy = 2, x, y > 0, then the value of (27x3 + y3) is:
Answer & Solution
Correct Answer:
Option
B
xy = 2
2 × 1
1 × 2
at x = 2, y = 1
9x2 + y2 = 37
9 × 4 + 1 = 37
37 = 37 it satisfy
27x3 + y3
= 27 × 23 + 13
= 27 × 8 + 1
= 217
2 × 1
1 × 2
at x = 2, y = 1
9x2 + y2 = 37
9 × 4 + 1 = 37
37 = 37 it satisfy
27x3 + y3
= 27 × 23 + 13
= 27 × 8 + 1
= 217
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