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If a = 0.1039, then the value of $$\sqrt {4{a^2} - 4a + 1} + 3a$$     is:

A. 0.1039

B. 0.2078

C. 1.1039

D. 2.1039

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & \sqrt {4{a^2} - 4a + 1} + 3a \cr & = \sqrt {{{\left( 1 \right)}^2} + {{\left( {2a} \right)}^2} - 2 \times 1 \times 2a} + 3a \cr & = \sqrt {{{\left( {1 - 2a} \right)}^2}} + 3a \cr & = \left( {1 - 2a} \right) + 3a \cr & = \left( {1 + a} \right) \cr & = \left( {1 + 0.1039} \right) \cr & = 1.1039 \cr} $$

This Question Belongs to Arithmetic Ability >> Square Root And Cube Root

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