If a = 2.361, b = 3.263, and c = 5.624, then the value of a3 + b3 - c3 + 3abc is?
A. (p- q)(q - r)3 + (r - p)3
B. 3(p - q)(q - r)(r - p)
C. 0
D. 1
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & a = 2.361 \cr & b = 3.263 \cr & c = 5.624 \cr & a + b - c = 0 \cr & 2.361 + 3.263 - 5.624 = 0 \cr & 0 = 0 \cr & \therefore {a^3} + {b^3} - {c^3} + 3abc \cr & \Rightarrow 0 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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