If $$a$$ and $$b$$ are the lengths of the sides of a right angled triangle whose hypotenuse is 10 and whose area is 20, then the value of ($$a$$ + $$b$$)2 is
A. 140
B. 120
C. 180
D. 160
Answer: Option C
Solution (By Examveda Team)
In right ΔABC,
a2 + b2 = 102 (by pt) . . . . (i)
Area ΔABC = $$\frac{1}{2}$$ ab = 20
ab = 40
(a + b)2 = a2 + b2 + 2ab
= 102 + 2(40)
= 180
This Question Belongs to Arithmetic Ability >> Geometry
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