If a + b = 1, find the value of a3 + b3 - ab - (a2 - b2)2 = ?
A. 0
B. 1
C. -1
D. 2
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & {\text{Let}} \cr & a = 0 \cr & b = 1 \cr & \Rightarrow {a^3} + {b^3} - ab - {\left( {{a^2} - {b^2}} \right)^2} \cr & \Rightarrow 0 + 1 - 0 - {\left( {0 - 1} \right)^2} \cr & \Rightarrow 1 - 1 \cr & \Rightarrow 0 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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