If a + b = 8 and a + a2b + b + ab2 = 128 then the positive value of a3 + b3 is:
A. 96
B. 224
C. 344
D. 152
Answer: Option D
Solution(By Examveda Team)
a + b = 8a + a2b + b + ab2 = 128
(a + b) + ab(a + b) = 128
(1 + ab)(a + b) = 128
1 + ab = 16
ab = 15
a3 + b3
= (a + b)3 - 3ab(a + b)
= 512 - 3 × 15 × 8
= 512 - 360
= 152
This Question Belongs to Arithmetic Ability >> Algebra
Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
Join The Discussion