If a, b are rationals and a√2 + b√3 = $$\sqrt {98} + \sqrt {108} - \sqrt {48} - \sqrt {72} ,$$      then the values of a, b are respectively

Solution (By Examveda Team)

$$\eqalign{ & a\sqrt 2 + b\sqrt 3 = \sqrt {98} + \sqrt {108} - \sqrt {48} - \sqrt {72} \cr & a\sqrt 2 + b\sqrt 3 = \sqrt {7 \times 7 \times 2} + \sqrt {3 \times 3 \times 3 \times 2 \times 2} - \sqrt {2 \times 2 \times 2 \times 2 \times 3} - \sqrt {3 \times 3 \times 2 \times 2 \times 2} \cr & a\sqrt 2 + b\sqrt 3 = 7\sqrt 2 + 6\sqrt 3 - 4\sqrt 3 - 6\sqrt 2 \cr & a\sqrt 2 + b\sqrt 3 = 1\sqrt 2 + 2\sqrt 3 \cr & a = 1 \cr & b = 2 \cr} $$