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If a + b + c = 2, $$\frac{1}{a} + \frac{1}{b} + \frac{1}{c}$$ = 0, ac = $$\frac{4}{b}$$ and a3 + b3 + c3 = 28, find the value of a2 + b2 + c2.
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& a + b + c = 2 \cr
& ab + bc + ca = 0 \cr
& abc = 4 \cr
& {a^3} + {b^3} + {c^3} - 3abc = \left( {a + b + c} \right)\left[ {\left( {{a^2} + {b^2} + {c^2}} \right) - \left( {ab + bc + ca} \right)} \right] \cr
& 28 - 3 \times 4 = 2\left( {{a^2} + {b^2} + {c^2}} \right) \cr
& {a^2} + {b^2} + {c^2} = 8 \cr} $$
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