If a + b + c = 6, a3 + b3 + c3 - 3abc = 342, then what is the value of ab + bc + ca?
A. 5
B. 8
C. -7
D. -5
Answer: Option C
Solution(By Examveda Team)
Let c = 0a + b = 6
a3 + b3 = 342
ab = ?
(a3 + b3) = (a + b)[(a + b)2 - 3ab]
342 = 6[62 - 3ab]
57 = 36 - 3ab
3ab = -21
ab = -7
This Question Belongs to Arithmetic Ability >> Algebra
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