If a + b + c = 8 and ab + bc + ca = 12, then a3 + b3 + c3 - 3abc is equal to:
A. 192
B. 224
C. 144
D. 400
Answer: Option B
Solution(By Examveda Team)
a + b + c = 8 and ab + bc + ca = 12a3 + b3 + c3 - 3abc = ?
Let c = 0
a + b = 8, ab = 12
a3 + b3 = (a + b)(a2 + b2 - ab)
a3 + b3 = (a + b)[(a + b)2 - 3ab]
a3 + b3 = 8[82 - 3 × 12]
a3 + b3 = 224
This Question Belongs to Arithmetic Ability >> Algebra
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