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If a, b, c are positive and a + b + c = 1, then the least value of $$\frac{1}{a}$$ + $$\frac{1}{b}$$ + $$\frac{1}{c}$$ is?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {\text{For minimum value of}} \cr
& \frac{1}{a} + \frac{1}{b} + \frac{1}{c} \cr
& a = b = c \cr
& a + b + c = 1{\text{ }}\left( {{\text{Given}}} \right) \cr
& \therefore a = b = c = \frac{1}{3} \cr
& \frac{1}{a} = \frac{1}{b} = \frac{1}{c} = 3 \cr
& \therefore {\text{Minimum value of,}} \cr
& = \frac{1}{a} + \frac{1}{b} + \frac{1}{c} \cr
& = 3 + 3 + 3 \cr
& = 9 \cr} $$
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