If 'a' is greater than 'b' by 2 and 'b' is greater than 'c' by 10 and a+b+c = 130, then (b+c)-a=?
A. 34
B. 42
C. 38
D. 44
Solution (By Examveda Team)
According to the question a = b + 2 and b = c +10
Therefore, c = b - 10,
Given, a + b + c = 130 (Put the value of 'a' and 'c').
we get, b + 2 + b + b - 10 =130.
next step: 3b = 138.
By solving above equation we get b = 46.
Therefore a = 48 and c = 36.
then (b + c) - a = 34.
so answer is 34.
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Q. Is wrong A is greater than C by 10 is right
34
Can you explain it in details plz.
According to the question
a-b=2 and b-c=10
So,a=b+2
And c=b-10
as the question said,
a+b+c=130
or,(b+2)+b+b-10=130
or,3b=138
So,b=46
Then putting the value of b we find a=(46+2)=48 and c=(46-10)=36
Therefore,(b+c)-a=34(Ans.)