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If a number of forces are acting at a point, their resultant will be inclined at an angle $$\theta $$ with the horizontal, such that

A. $$\tan \theta = \frac{{\sum {\text{H}} }}{{\sum {\text{V}} }}$$

B. $$\tan \theta = \frac{{\sum {\text{V}} }}{{\sum {\text{H}} }}$$

C. $$\tan \theta = \sum {{\text{V}} \times \sum {\text{H}} } $$

D. $$\tan \theta = \sqrt {\sum {{\text{V}} + \sum {\text{H}} } } $$

Answer: Option B


This Question Belongs to Mechanical Engineering >> Engineering Mechanics

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Comments ( 2 )

  1. Jenedip Lakra
    Jenedip Lakra :
    3 years ago

    In a machine whose velocity ratio is 6 an effort of 20n was able to lift a load of 100n find its mechanical advantage

  2. Jenedip Lakra
    Jenedip Lakra :
    3 years ago

    The resultant of two forces p&q acting at an angle thita is

Related Questions on Engineering Mechanics

If a number of forces are acting at a point, their resultant is given by

A. $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2}$$

B. $$\sqrt {{{\left( {\sum {\text{V}} } \right)}^2} + {{\left( {\sum {\text{H}} } \right)}^2}} $$

C. $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2} + 2\left( {\sum {\text{V}} } \right)\left( {\sum {\text{H}} } \right)$$

D. $$\sqrt {{{\left( {\sum {\text{V}} } \right)}^2} + {{\left( {\sum {\text{H}} } \right)}^2} + 2\left( {\sum {\text{V}} } \right)\left( {\sum {\text{H}} } \right)} $$