If $${a^2} + \frac{2}{{{a^2}}} = 16,$$ then find the value of $$\frac{{72{a^2}}}{{{a^4} + 2 + 8{a^2}}}.$$
A. 3
B. 1
C. 4
D. 2
Answer: Option A
Solution (By Examveda Team)
$$\eqalign{ & {a^2} + \frac{2}{{{a^2}}} = 16 \cr & \frac{{72{a^2}}}{{{a^4} + 2 + 8{a^2}}} \cr & = \frac{{72}}{{{a^2} + \frac{2}{{{a^2}}} + 8}} \cr & = \frac{{72}}{{16 + 8}} \cr & = 3 \cr} $$This Question Belongs to Arithmetic Ability >> Algebra
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