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If $${a^2} + \frac{2}{{{a^2}}} = 16,$$ then find the value of $$\frac{{72{a^2}}}{{{a^4} + 2 + 8{a^2}}}.$$
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {a^2} + \frac{2}{{{a^2}}} = 16 \cr
& \frac{{72{a^2}}}{{{a^4} + 2 + 8{a^2}}} \cr
& = \frac{{72}}{{{a^2} + \frac{2}{{{a^2}}} + 8}} \cr
& = \frac{{72}}{{16 + 8}} \cr
& = 3 \cr} $$
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