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If a2 = b + c, b2 = a + c, c2 = b + a, then what will be the value of $$\frac{1}{{a + 1}}$$ + $$\frac{1}{{b + 1}}$$ + $$\frac{1}{{c + 1}}$$ ?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& {a^2} = b + c,{\text{ }}{b^2} = a + c,{\text{ }}{c^2} = b + a \cr
& {\text{Taking }}a = 2,{\text{ }}b = 2{\text{ and }}c = 2 \cr
& {\text{So,}}{\left( 2 \right)^2} = 2 + 2 \cr
& \boxed{4 = 4} \cr
& {\text{Now,}}\frac{1}{{a + 1}} + {\text{ }}\frac{1}{{b + 1}} + {\text{ }}\frac{1}{{c + 1}} \cr
& {\text{Put }}a = 2,{\text{ }}b = 2{\text{ and }}c = 2 \cr
& = \frac{1}{{2 + 1}} + {\text{ }}\frac{1}{{2 + 1}} + {\text{ }}\frac{1}{{2 + 1}} \cr
& = \frac{1}{3} + \frac{1}{3} + \frac{1}{3} \cr
& = 1 \cr} $$
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