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If $${a^3} + \frac{1}{{{a^3}}} = 2{\text{,}}$$ then the value of $$\frac{{{a^2} + 1}}{a}$$ is (a positive number) ?
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& {\text{But }}a = 1 \cr
& {a^3} + \frac{1}{{{a^3}}} = 2 \cr
& \Rightarrow {1^3} + \frac{1}{{{1^3}}} = 2 \cr
& \Rightarrow 2 = 2{\text{ }}\left( {{\text{Satisfy}}} \right) \cr
& {\text{So, }}\frac{{{a^2} + 1}}{a} \cr
& = \frac{{{1^2} + 1}}{1} \cr
& = 2 \cr} $$
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