If a2 + b2 + c2 = ab + bc + ca, then the value of $$\frac{{a + c}}{b}$$ is?
A. 0
B. 2
C. 1
D. 3
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {\text{According to the question,}} \cr & {a^2} + {b^2} + {c^2} = ab + bc + ca \cr & {\text{Put }}a = 1 \cr & b = 1 \cr & c = 1 \cr & \therefore {a^2} + {b^2} + {c^2} = ab + bc + ca \cr & \Rightarrow {1^2} + {1^2} + {1^2} = 1 \times 1 + 1 \times 1 + 1 \times 1 \cr & \Rightarrow 1 + 1 + 1 = 1 + 1 + 1 \cr & \Rightarrow 3 = 3{\text{ }}\left( {{\text{Satisfy}}} \right) \cr & \therefore \frac{{a + c}}{b} \cr & = \frac{{1 + 1}}{1} \cr & = 2 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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