If a3 + b3 = 218 and a + b = 2, then the value of $$1 - \sqrt {ab} $$ is:
A. 5
B. 3
C. 4
D. 6
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & {a^3} + {b^3} = 218\,\& \,a + b = 2 \cr & {\left( {a + b} \right)^3} = {\left( 2 \right)^3} \cr & {a^3} + {b^3} + 3\left( {a + b} \right)\left( {ab} \right) = 8 \cr & 218 + 3\left( 2 \right)\left( {ab} \right) = 8 \cr & ab = \frac{{8 - 218}}{6} \cr & ab = \frac{{ - 210}}{6} = - 35 \cr & \sqrt {1 - ab} = \sqrt {1 - \left( { - 35} \right)} \cr & \sqrt {1 - ab} = \sqrt {1 + \left( {35} \right)} \cr & \sqrt {1 - ab} = 6 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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